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NEW QUESTION: 1
A. Option D
B. Option B
C. Option C
D. Option A
Answer: C
Explanation:
* Scenario: A group of junior database administrators must be able to view the server state of the SQL Server instance that hosts the Sales database. The junior database administrators will not have any other administrative rights.
* Credentials provide a way to allow SQL Server Authentication users to have an identity outside of SQL Server. Credentials can also be used when a SQL Server Authentication user needs access to a domain resource, such as a file location to store a backup. Create a Credential
NEW QUESTION: 2
What is one reason to choose HP Intelligent Management Center (IMC) Enterprise edition rather than HP IMC Standard edition?
A. The customer needs a distributed deployment, in which different IMC components are deployed to different servers.
B. The customer needs to be able to choose IMC add-on modules and add them to the IMC solution.
C. The customer needs the most cost-effective option for managing a network with about 200 nodes.
D. The customer needs a hierarchical deployment, in which different servers manage different segments of the network.
Answer: A
NEW QUESTION: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.1.0.0.0.254
B. Permit 10.0.0.0.0.0.0.1
C. Permit 10.0.0.0.255.255.255.254
D. Permit 10.0.0.1.0.0.0.0
Answer: A
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 000 ) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.