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NEW QUESTION: 1
A pharmacist at an independent compounding pharmacy needs to concoct a batch of "LMAO". The
formula calls for: Drug L -0.1 Kilo Drug M -5600 mg Drug A -0.5 lb Drug O -100 grams
After the batch is prepared it will be used to press 600mg tabs, How many whole tabs will be made?
A. 0
B. 1
C. 2
D. 3
Answer: A
NEW QUESTION: 2
Which Cisco Unified Contact Center Express data store contains CSQ information?
A. repository data store
B. script data store
C. historical data store
D. agent data store
E. configuration data store
Answer: E
Explanation:
Explanation/Reference:
The Database component is required for any Unified CCX deployment and manages access to the database. The Unified CCX Database contains four data stores. They are as follows:
The configuration data store contains Unified CCX configuration information such as resources (agents), skills, resource groups, teams, and CSQ information. The repository data store contains user prompts, grammars, and documents. The agent data store contains agent logs, statistics, and pointers to the recording files. The historical data store contains Contact Call Detail Records (CCDRs).
Reference:
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cust_contact/contact_center/crs/express_9_ 02/ design/guide/UCCX_BK_C39FDB35_00_cisco-unified-contact-center- express/ UCCX_BK_C39FDB35_00_cisco-unified-contact-center-express_chapter_010.html
NEW QUESTION: 3
View the Exhibit and examine the data in the PROJ_TASK_DETAILS table.
The PROJ_TASK_DETAILS table stores information about tasks involved in a project and the relation between them.
The BASED_ON column indicates dependencies between tasks. Some tasks do not depend on the completion of any other tasks.
You need to generate a report showing all task IDs, the corresponding task ID they are dependent on, and the name of the employee in charge of the task it depends on.
Which query would give the required result?
A. SELECT p.task_id, p.based_on, d.task_in_charge FROM proj_task_details p JOIN proj_task_details d ON (p.task_id = d.task_id);
B. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p FULL OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
C. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p LEFT OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
D. SELECT p.task_id, p.based_on, d.task_in_charge FROM proj_task_details p JOIN proj_task_details d ON (p.based_on = d.task_id);
Answer: C
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