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NEW QUESTION: 1
온라인 게임에 대한 플레이어 점수를 저장하는 앱이 있습니다. 앱은 테이블 엔티티로 PlayerScore라는 클래스를 사용하여 Azure 테이블에 데이터를 저장합니다. 테이블에는 100,000 개의 레코드가 채워집니다.
플레이어 점수가 15,000을 초과하는 20 개의 레코드를 검색하기위한 다음 코드 섹션을 검토하고 있습니다. (라인 번호는 참고 용으로 만 포함됩니다.)
다음과 같은 코드가 있습니다. (라인 번호는 참조 용으로 만 포함됩니다.) Azure Cosmos 데이터베이스에 고객 정보를 저장합니다. 다음 데이터가 이미 데이터베이스에 있습니다.
다음 코드를 개발합니다. (라인 번호는 참고 용으로 만 포함됩니다.)
다음 명령문 각각에 대해 명령문이 참이면 예를 선택하십시오. 그렇지 않으면 아니오를 선택하십시오.
참고 : 각각의 올바른 선택은 한 점으로 가치가 있습니다.
Answer:
Explanation:
설명
상자 1 : 아니오
상자 2 : 예
TableQuery.Take 메서드는 쿼리에서 반환하는 엔터티 수의 상한을 정의합니다.
예:
query.Take (10);
박스 3 : 예
상자 4 : 예
참고 문헌 :
https://www.vkinfotek.com/azureqa/how-do-i-query-azure-table-storage-using-tablequery-class.html
NEW QUESTION: 2
DRAG DROP
You are building a fact table in a data warehouse.
The table must have a columnstore index. The table cannot be partitioned.
You need to design the fact table and load it with data.
Which three actions should you perform in sequence? (To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.) Select and Place:
Answer:
Explanation:
Explanation/Reference:
Explanation:
Only nonclustered columnstore indexes are available in SQL Server 2012 so when the index is created, you cannot update the table (without using partition switching). Therefore you have to load the data BEFORE creating the index.
In SQL Server 2014, you could create a clustered columnstore index which would allow updates to the table after the index is created.
NEW QUESTION: 3
Refer to the exhibit.
An integrator needs to add an FCoE connection to the server profile, but the FCoE connection type is not available.
What is the likely cause of this issue?
A. A FCoE connection is not available, as there is no LIG configured for FCoE connectivity
B. FCoE capable interconnect modules are not installed in the Synergy frame
C. The FCoE connection has not been added as a Fibre Channel connection within a server profile
D. Defined FCoE network is not associated with a SAN or does not have VLAN Id defined
Answer: C
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