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NEW QUESTION: 1
Which of the following connectors would be used to connect the cable leading to the power supply to an IDE hard disk drive?
A. Molex
B. Lightning
C. BNC
D. SCSI
Answer: A

NEW QUESTION: 2
Which are capabilities of Avaya Contact Center Select (ACCS)? (Select four.)
A. Home worker agents
B. Multimedia agents
C. Customer satisfaction surveys
D. Call recording
E. Outbound calling campaigns
Answer: A,B,D,E

NEW QUESTION: 3







A. Option C
B. Option B
C. Option D
D. Option A
Answer: D
Explanation:
Explanation
On the new switch, we see that loopguard has been configured with the "spanning-tree guard loop" command.

The loop guard feature makes additional checks. If BPDUs are not received on a non-designated port, and loop guard is enabled, that port is moved into the STP loop-inconsistent blocking state, instead of the listening / learning / forwarding state. Without the loop guard feature, the port assumes the designated port role. The port moves to the STP forwarding state and creates a loop.

NEW QUESTION: 4
You have a database that contains the following tables.

You need to create a query that lists all complaints from the Complaints table, and the name of the person handling the complaints if a person is assigned. The ComplaintID must be displayed first, followed by the person name.
Construct the query using the following guidelines:
- Use two-part column names.
- Use one-part table names.
- Do not use aliases for column names or table names.
- Do not use Transact-SQL functions.
- Do not use implicit joins.
- Do not surround object names with square brackets.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within the code that has been provided as well as below it.


Use the Check Syntax button to verify your work. Any syntax or spelling errors will be reported by line and character position.
Answer:
Explanation:
SELECT
Complaints.ComplaintID, Persons.Name
FROM
Complaints LEFT OUTER JOIN Contacts ON Complaints.ComplaintID =
Contacts.ComplaintID
LEFT OUTER JOIN Persons ON Contacts.PersonID = Persons.PersonID