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NEW QUESTION: 1
SQL Server 2012がインストールされているSQL1とSQL2という名前の2つのサーバーがあります。
SQL1には、SQL2と非同期にミラーリングされているデータベースが含まれています。 データベースの内容は月に一度更新されます。
データベースをSQL Server 2014にアップグレードする必要があります。このソリューションでは、ダウンタイムを最小限に抑える必要があります。 どのアップグレード手順をお勧めしますか? 答えるには、適切な行動を行動のリストから回答領域に移動し、正しい順序で並べます。
Answer:
Explanation:
Explanation
References:https://docs.microsoft.com/en-us/sql/database-engine/database-mirroring/upgrading-mirrored-instanc
NEW QUESTION: 2
DRAG DROP
On the left are various network protocols. On the right are the layers of the TCP/IP model. Assuming a reliable connection is required, move the protocols on the left to the TCP/IP layers on the right to show the proper encapsulation for an email message sent by a host on a LAN. (Not all options are used.)
Answer:
Explanation:
NEW QUESTION: 3
View the Exhibit and examine the structure of the PRODUCTS tables.
You want to generate a report that displays the average list price of product categories where the average list price is less than half the maximum in each category.
Which query would give the correct output?
A. SELECT prod_category,avg(prod_list_price) FROM products GROUP BY prod_category HAVING avg(prod_list_price) > ANY (SELECT max(prod_list_price)/2 FROM products);
B. SELECT prod_category,avg(prod_list_price) FROM products HAVING avg(prod_list_price) < ALL (SELECT max(prod_list_price)/2 FROM products GROUP BY prod_category);
C. SELECT prod_category,avg(prod_list_price) FROM products GROUP BY prod_category HAVING avg(prod_list_price) < ALL (SELECT max(prod_list_price)/2 FROM products GROUP BY prod_category);
D. SELECT prod_category,avg(prod_list_price) FROM products GROUP BY prod_category HAVING avg(prod_list_price) > ANY (SELECT max(prod_list_price)/2 FROM products GROUP BY prod_category);
Answer: C
Explanation:
Using the ANY Operator in Multiple-Row Subqueries
The ANY operator (and its synonym, the SOME operator) compares a value to each value
returned by a subquery.
<ANY means less than the maximum.
>ANY means more than the minimum.
=ANY is equivalent to IN
Using the ALL Operator in Multiple-Row Subqueries
The ALL operator compares a value to every value returned by a subquery.
>ALL means more than the maximum and
<ALL means less than the minimum.
The NOT operator can be used with IN, ANY, and ALL operators.