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NEW QUESTION: 1
Drag and drop the BGP terms from the left onto the correct descriptions on the right
Answer:
Explanation:
Explanation
external BGP = peers are in different autonomous systems (AS)
internal BGP = peers are in the same autonomous systems
Autonomous System = separate network operating within one administrative domain Private autonomous system (AS)= numbers which range from 64512 to 65535 Public AS = between 1 and 64511 Prefix = block of ip addresses
NEW QUESTION: 2
An enterprise customer has recently purchased a WAN link from a service provider. BGP is running over this WAN link. An engineer notices that the CE router uses an large amount of system resources to process routing updates by filtering out unwanted routing updates received from the PE, which configuration can be applied to reduce the amount of processing required on the CE router that is not accepting full routes from PE?
A. On CE, apply an outbound route-map on BGP PE-neighbor to filter all the undesired BGP updates learned from the PE
B. Enable BGP flowspec between CE and PE to negotiate which BGP prefixes to advertise
C. On CE place an inbound ACL on the interface-facing PE to filter all unwanted BGP prefixes
D. Enable the BGP prefix-based ORF capability CE and PE to filter out unwanted routing updates at the source
Answer: D
NEW QUESTION: 3
Internal users are reporting high latency when connecting to external servers in the cloud. Which of the following should a network administrator optimize?
A. VLAN
B. SAN
C. LAN
D. WAN
Answer: D
NEW QUESTION: 4
*Item_ID, Integer: PK
*Item_name, Varchar (20)
*Price, Numeric (10, 2)
*Quan, Integer
public static void updatePrices{ // #1: missing line
Connection con) throws SQLException {
// #2: missing line
PreparedStatement updatePrices = con.prepareStatement (updatePricesString);
// #3: missing line { // #4: missing line updatePrices.executeUpdate(); } }
A. 1. HashMap<Integer, String> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? WHERE item_name '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setFloat(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getKey());
B. 1. HashMap<Integer, Float> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setInt(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getvalue());
C. 1. HashMap<Integer, String> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices,setString(1, x.getKey()); updatePrices.setFloat(2, x.getValue().floatValue());
D. 1. HashMap<Integer, Float> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setInt(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getvalue().floatValue()
E. 1. HashMap<Integer, Float> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? WHERE item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setFloat(1, x.getvalue().floatValue()); updatePrice.setString (2,
x.getKey().intValue());
F. 1. HashMap<Integer> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (Integer x: newPrice)
4.updatePrice.setInt(1, x);
Answer: D
Explanation:
The first line should be HashMap<Integer, Float> newPrices,
as in SQL numeric represent a float number, not an integer or string.
We also make sure to use floatValue() both in appropriate places in line 4.
Note: Map is an object that maps keys to values. A map cannot contain duplicate keys: Each key
can map to at most one value. It models the mathematical function abstraction.
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