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NEW QUESTION: 1
Which statement about Cisco WebEx Meeting Center is true?
A. It displays life-size, remarkably clear video images, which provide a "face-to-face" meeting with remote customers, suppliers, and partners.
B. It is powered by Jabber XMPP and can be used for one-on-one or group chat and File transfers.
C. It is an award-winning flagship product that simulates a traditional live meeting in an online environment.
D. It is fully scalable, is delivered entirely over the public internet, and is optimized for security, performance, and reliability.
Answer: C
NEW QUESTION: 2
メディア顧客は、AWSアカウントに数千のAmazon EC2インスタンスを持っています。お客様は、チームのコミュニケーションと重要な更新のためにSlackチャネルを使用しています。 DevOpsエンジニアは、AWSがスケジュールしたすべてのEC2メンテナンス通知を会社のSlackチャネルに送信するように指示されました。エンジニアがこのプロセスを最小限のステップで実装するために使用する方法はどれですか?
A. AWS Personal Health DashboardをAmazon CloudWatch Eventsと統合します。作成されたCloudWatchイベントに基づいて、イベントはAWS Lambda関数を呼び出してSlackチャネルに通知を送信できます。
B. AWSサポートをAWS CloudTrailと統合します。作成されたCloudTrailルックアップイベントに基づいて、イベントはAWS Lambda関数を呼び出し、EC2メンテナンス通知をSlackチャネルに渡すことができます。
C. EC2イベントをAmazon CloudWatchモニタリングと統合します。作成されたCloudWatchアラームに基づいて、アラームはAWS Lambda関数を呼び出し、EC2メンテナンス通知をSlackチャネルに送信できます。
D. AWS Trusted AdvisorとAWS Configを統合します。作成されたAWS Configルールに基づいて、AWS ConfigイベントはAWS Lambda関数を呼び出して通知をSlackチャネルに送信できます。
Answer: A
Explanation:
Explanation
https://docs.aws.amazon.com/health/latest/ug/cloudwatch-events-health.html
NEW QUESTION: 3
CORRECT TEXT
Which of the following is an advantage of prototyping?
A. The finished system normally has strong internal controls.
B. Change control is often less complicated with prototype systems.
C. it ensures that functions or extras are not added to the intended system.
D. Prototype systems can provide significant time and cost savings.
Answer: D
Explanation:
Prototype systems can provide significant time and cost savings; however, they also have several disadvantages. They often have poor internal controls, change control becomes much more complicated, and it often leads to functions or extras being added to the system that were not originally intended.
NEW QUESTION: 4
Consider the Information Engineering diagram shown in the exhibit. Building_ID, R_ID, Room_Count and Room_Num are integer numbers, whereas Bldg_Name, Location and Res_Name are all represented by variable-length strings with a maximum of 20 characters.
Which SQL statement best implements the RESIDENT relation shown in this diagram?
A. CREATE TABLE RESIDENT (
R_ID INTEGER NOT NULL PRIMARY KEY,
Room_NumINTEGER,
Res_NameVARCHAR (20),
Building_IDINTEGER NOT NULL);
B. CREATE TABLE RESIDENT (
R_ID INTEGER NOT NULL PRIMARY KEY,
Room_NumBINARY,
Res_NameVARCHAR (20),
Building_IDINTEGER NOT NULL,
FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID));
C. CREATE TABLE RESIDENT (
R_ID INTEGER NOT NULL PRIMARY KEY,
Room_NumINTEGER,
Res_NameVARCHAR (20),
Building_IDINTEGER NOT NULL,
FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID));
D. CREATE TABLE RESIDENT (
R_ID INTEGER NULL PRIMARY KEY,
Room_NumFLOAT,
Res_NameVARCHAR,
Building_IDINTEGER NULL,
FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID));
Answer: C