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NEW QUESTION: 1
An administrator has defined a backup policy. Full backups will be performed at 8 PM every Monday and incremental backups performed at 8 PM the remaining days.
How many backup copies are required to restore the files if they were accidentally deleted on Friday morning?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 2
Which protocol does the Cisco Prime LAN Management Solution application use to communicate with
3 / 162
The safer , easier way to help you pass any IT exams.
Cisco EnergyWise domain members?
A. Cisco Discovery Protocol
B. multicast
C. UDP unicast
D. UDP broadcast
E. TCP
Answer: E
Explanation:
Explanation/Reference:
Explanation:
Cisco Prime LMS 4.1 uses TCP port 43440.
NEW QUESTION: 3
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
B. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
C. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
D. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
Answer: D
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network 10.10.10.0/24 is 20 + 50 = 70.
Before a router can be considered a feasible successor, it must pass the feasibility condition rule. In short, the feasibility condition says that if we learn about a prefix from a neighbor, the advertised distance from that neighbor to the destination must be lower than our feasible distance to that same destination. Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the feasibility condition.
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