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NEW QUESTION: 1

Refer to the architecture diagram above of a batch processing solution using Simple Queue Service (SOS) to set up a message queue between EC2 instances which are used as batch processors Cloud Watch monitors the number of Job requests (queued messages) and an Auto Scaling group adds or deletes batch servers automatically based on parameters set in Cloud Watch alarms. You can use this architecture to implement which of the following features in a cost effective and efficient manner?
A. Coordinate number of EC2 instances with number of job requests automatically thus Improving cost effectiveness.
B. Handle high priority jobs before lower priority jobs by assigning a priority metadata field to SQS messages.
C. Implement fault tolerance against EC2 instance failure since messages would remain in SQS and worn can continue with recovery of EC2 instances implement fault tolerance against SQS failure by backing up messages to S3.
D. Implement message passing between EC2 instances within a batch by exchanging messages through SOS.
E. Reduce the overall lime for executing jobs through parallel processing by allowing a busy EC2 instance that receives a message to pass it to the next instance in a daisy-chain setup.
Answer: C

NEW QUESTION: 2
Examine the following output:
[oracle@gr5153~]$srvctl add service -d RACDB -s erp -g pool1 -c uniform -y manual
[oracle0gr5153~]$srvctl start service -d RACDB -s ERP
[oracle@gr5153~]$crsctl stat res ora.racdb.erp.svc NAME=ora.racdb.erp.svc TYPE=ora.service.type TARGET=ONLINE, ONLINE, ONLINE STATE=ONLINE on gr5118, ONLINE on gr5152, ONLINE on gr5153
[oracle@gr5153~]$ srvctl config database -d RACDB
Database unique name: RACDB
Database name: RACDB
Oracle home:/u01/app/oracle/product/11.2.0/dbhome_1
Oracle user:oracle
Spfile:+DATA/RACDB/spfileRACDB.ora
Domain:
Start options:open
Stop options:immediate
Database role:PRIMARY
Management policy:AUTOMATIC
Server pools:POOL 1
Database instances:
Disk Groups:DATA, FRA
Services:ERP
Database is policy managed
$srvctl stop database -d RACDB -o immediate
Which two statements are true regarding the srvctl stop command?
A. It will stop the ERP service related to the RACDB database on all the nodes.
B. It will shut down only the database instance on the node on which the command is executed.
C. It will shut down all the instances of the RACDB database.
D. It will shut down only the RACDB instance and the ERP service on the node on which the Command is executed.
Answer: A,C
Explanation:
Explanation/Reference:
Explanation:
Shut down all Oracle RAC instances on all nodes. To shut down all Oracle RAC instances for a database, enter the following command, where db_name is the name of the database:
srvctl stop database -d db_name
Stops a database, its instances, and its services. When the database later restarts, services with AUTOMATIC management start automatically but services with MANUAL management policy must be started manually.
Oracle Real Application Clusters Administration and Deployment Guide

NEW QUESTION: 3
展示を参照してください。

WLCのインターフェイスがRADIUSサーバーと同じサブネットにない場合、WLCはすべてのRADIUS関連トラフィックのソースとしてどのインターフェイスを使用しますか？
A. コントローラー仮想インターフェース
B. WLAN構成で指定されたインターフェース
C. WLCで構成されているすべてのインターフェイス
D. コントローラー管理インターフェース
Answer: B

NEW QUESTION: 4
Consider the Information Engineering diagram shown in the exhibit for a building management company.
Referential integrity must be maintained such that a building cannot be deleted when it has residents.
Building_ID, R_ID, Room_Count and Room_Num are integer numbers, whereas Bldg_Name, Location and Res_Name are all represented by variable-length strings with a maximum of 20 characters. Which SQL statement best implements the relations shown in this diagram?

A. CREATE TABLE BUILDING (
Building_ID INTEGER NOT NULL PRIMARY KEY,
Bldg_Name VARCHAR (20),
Location VARCHAR (20),
Room_Count INTEGER );
CREATE TABLE RESIDENT (
R_ID NOT NULL PRIMARY KEY,
Room_Num INTEGER,
Res_Name VARCHAR (20),
Building_ID INTEGER NOT NULL,
FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID)
ON DELETE NO CHECK
ON UPDATE CASCADE);
B. CREATE TABLE BUILDING (
Building_ID INTEGER NOT NULL PRIMARY KEY,
Bldg_Name VARCHAR (20),
Location VARCHAR (20),
Room_Count INTEGER );
CREATE TABLE RESIDENT (
R_ID NOT NULL PRIMARY KEY,
Room_Num INTEGER,
Res_Name VARCHAR (20),
Building_ID INTEGER NOT NULL,
FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID)
ON DELETE NO CHECK
ON UPDATE CASCADE);
C. CREATE TABLE BUILDING (
Building_ID INTEGER NOT NULL PRIMARY KEY,
Bldg_Name VARCHAR (20),
Location VARCHAR (20),
Room_Count INTEGER );
CREATE TABLE RESIDENT (
R_ID NOT NULL PRIMARY KEY,
Room_Num INTEGER,
Res_Name VARCHAR (20),
Building_ID INTEGER NOT NULL,
FOREIGN KEY Building_ID REFERENCES BUILDING (Building_ID)
ON DELETE NO CHECK
ON UPDATE CASCADE);
D. CREATE TABLE BUILDING (
Building_ID INTEGER NOT NULL PRIMARY KEY,
Bldg_Name VARCHAR (20),
Location VARCHAR (20),
Room_Count INTEGER );
CREATE TABLE RESIDENT (
R_ID NOT NULL PRIMARY KEY,
Room_Num INTEGER,
Res_Name VARCHAR (20),
Building_ID INTEGER NOT NULL,
FOREIGN KEY Building_ID REFERENCES RESIDENT (Building_ID)
ON DELETE NO CHECK);
Answer: C