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NEW QUESTION: 1
What does the command terraform fmt do?
A. deletes the existing configuration file
B. updates the font of the configuration file to the official font supported by HashiCorp
C. formats the state file in order to ensure the latest state of resources can be obtained
D. rewrite Terraform configuration files to a canonical format and style
Answer: D
Explanation:
The terraform fmt command is used to rewrite Terraform configuration files to a canonical format and style. This command applies a subset of the Terraform language style conventions, along with other minor adjustments for readability.
Other Terraform commands that generate Terraform configuration will produce configuration files that conform to the style imposed by terraform fmt, so using this style in your own files will ensure consistency.
NEW QUESTION: 2
Given:
public class Canvas implements Drawable {
public void draw () { }
}
public abstract class Board extends Canvas { }
public class Paper extends Canvas {
protected void draw (int color) { }
}
public class Frame extends Canvas implements Drawable {
public void resize () { }
}
public interface Drawable {
public abstract void draw ();
}
どちらの説明が正しいですか？
A. Board does not compile.
B. All classes compile successfully.
C. Frame does not compile.
D. Drawable does not compile.
E. Paper does not compile.
Answer: B
NEW QUESTION: 3
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?
A. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
0:00:16, FastEthemet0/0
B. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
0:00:16, Serial1/0
0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
90.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via
1
0
190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets ->
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.
NEW QUESTION: 4
Refer to the exhibit. Which tables correctly map the HIF ports to active FEX NIF ports on a Cisco UCS
2208X IOM in discrete pinning mode?
A. Table 2 and Table 4
B. Table 3 and Table 4
C. Table 1 and Table 2
D. Table 1 and T able 4
E. Table 2 and Table 3
Answer: D
Explanation:
Explanation/Reference:
Reference:
http://www.cisco.com/c/en/us/td/docs/unified_computing/ucs/ts/guide/UCSTroubleshooting/UCST roubleshooting_chapter_01001.html
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