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NEW QUESTION: 1
What information is provided when you execute the balance audit trail?
Response:
A. The open account balances for customer accounts and supplier accounts
B. The starting balance and the yearly changes to the balance of a general ledger account
C. A list of changes of maintained sensitive fields in general ledger accounts
D. A comparison of general ledger account balances across ledgers
Answer: D
Explanation:
https://help.sap.com/doc/2a3ddc52a1d5be66e10000000a441470/3.7/en-
US/909fd35659f3f577e10000000a4450e5.html
NEW QUESTION: 2
You are a consultant and set up Dynamics 365 for Finance and Operations for local and multinational companies.
You need to establish policy rules for purchasing.
What policy frameworks should you implement for each scenario? To answer, the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation
References:
https://docs.microsoft.com/en-us/dynamics365/unified-operations/supply-chain/procurement/purchase-policies
NEW QUESTION: 3
Which address would successfully summarize only the networks seen?
A. 192.168.0.0/24
B. 192.168.8.0/20
C. 192.168.8.0/21
D. 192.168.12.0/20
E. These networks cannot be summarized.
F. 192.168.16.0/21
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number if subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21.
If you make it an binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 00001 000
9 00001 001
10 00001 010
11 00001 011
12 00001 100
13 00001 101
14 00001 110
15 00001 111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0
NEW QUESTION: 4
A. Option B
B. Option D
C. Option C
D. Option A
Answer: D
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