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NEW QUESTION: 1
Which of the following DITSCAP phases validates that the preceding work has produced an IS that operates in a specified computing environment?
A. Phase 1
B. Phase 2
C. Phase 4
D. Phase 3
Answer: D
NEW QUESTION: 2
You are a wireless network administrator for ABC Corporation. Currently ABC Corp has a VPN concentrator that uses a PPTP/MS-CHAPv2/MPPE-128 VPN security solution for its 100 WLAN users. Since the WLAN was installed, there have been multiple successful attacks against ABC Corp's access points since they are using Open System authentication. ABC Corp wants to update their WLAN security solution. Which security solution would improve the security of ABC Corp's access points while increasing encryption strength and network scalability?
A. L2TP/IPSec with AES-192
B. WEP with Shared Key authentication
C. SSH2 with 3DES
D. WPA2-Enterprise with EAP-TTLS
Answer: D
Explanation:
ThisQUESTION NO:has to do with the architecture of ABC Corp's wireless design and securityimplementation. The current design provides for a fully open access point, with a VPNconcentrator residing behind the AP on the wired network. Security is implemented throughclient-to-VPN concentrator encrypted connections; however, the wireless medium is fully open.In order to address the requirement of 'improve the security of the access points' L2TP/IPSecwith AES-192 and SSH2 with 3DES are out. These options (IPSec and SSH) enhance or alterthe encryption tools and techniques used to connect the client and internal security devices. These options donot alter the access point itself, which is still left open.Both options WPA2-Enterprise with EAP-TTLS and WEP with Shared Key authenticationprovide better security to the AP itself; however, static WEP is significantly less secure thanusing WPA2 with EAP. Further, EAP will scale better than needing to manually configure staticWEP keys on each of the clients and AP devices.
NEW QUESTION: 3
Third grade student Stephanie Wink goes to the school nurse's office, where her temperature is found to be 98 degrees Fahrenheit. What is her temperature in degrees Celsius?
A. 35.8
B. 22.4
C. 36.7
D. 37.6
E. 31.1
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Use the formula beginning with the operation in parentheses: 98 minus 32 equals 66. Then multiply 66 by
5/9, first multiplying 66 by 5 to get 330. 330 divided by 9 is 36.66667, which is rounded up to 36.7.