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NEW QUESTION: 1
あなたの会社はDynamoDBをバックエンドデータストアとして使用してハイスコアを保存するモバイルゲームを作成しています。メインテーブルにはハッシュ+範囲キーがあります。ゲームはパーティションキー、ユーザー名はソートキーです。あなたの最も売れているゲームの顧客はあなたのバックエンドにハイスコアを送ろうとするとあなたのゲームが停止するまで遅くなると文句を言います。 CloudWatchメトリクスは、プロビジョニングされたWCUを超えていないことを示唆しています。コストを増やすことなくユーザーエクスペリエンスを向上させることができるオプションはどれですか？
2正しい答えを選んでください。
A. デバイスIDをパーティションキーとして使用し、ゲーム名をソートキーとして使用するようにパーティションキーを変更します。
B. パーティションキーとしてユーザー名を使用し、ソートキーとしてゲームを使用するようにパーティションキーを変更します。
C. ゲームだけを使うようにパーティションキーを変更する
D. より多くのWCUをプロビジョニングします
Answer: A,B
Explanation:
You are getting hot keys, need to spread create keys that are spread out, both usernames and device IDs can do that

NEW QUESTION: 2
You are developing an application that will convert data into multiple output formats.
The application includes the following code. (Line numbers are included for reference only.)

You are developing a code segment that will produce tab-delimited output. All output routines implement the following interface:

You need to minimize the completion time of the GetOutput() method.
Which code segment should you insert at line 06?

A. Option B
B. Option C
C. Option A
D. Option D
Answer: A
Explanation:
Explanation/Reference:
Explanation:
A String object concatenation operation always creates a new object from the existing string and the new data.
A StringBuilder object maintains a buffer to accommodate the concatenation of new data. New data is appended to the buffer if room is available; otherwise, a new, larger buffer is allocated, data from the original buffer is copied to the new buffer, and the new data is then appended to the new buffer.
The performance of a concatenation operation for a String or StringBuilder object depends on the frequency of memory allocations. A String concatenation operation always allocates memory, whereas a StringBuilder concatenation operation allocates memory only if the StringBuilder object buffer is too small to accommodate the new data. Use the String class if you are concatenating a fixed number of String objects. In that case, the compiler may even combine individual concatenation operations into a single operation. Use a StringBuilder object if you are concatenating an arbitrary number of strings; for example, if you're using a loop to concatenate a random number of strings of user input.
References: http://msdn.microsoft.com/en-us/library/system.text.stringbuilder(v=vs.110).aspx

NEW QUESTION: 3
Hotspot Question
You are working for a company that designs mobile applications. They maintain a server where player records are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process. (Line numbers are included for reference only.)

For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder) {
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}