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NEW QUESTION: 1
When is it most appropriate for a Development Team to change the definition of "Done"?
A. Prior to starting a new project.
B. Prior to starting a new Sprint.
C. During Spring Planning.
D. During the Sprint Retrospective.
Answer: D
NEW QUESTION: 2
You are configuring a new Microsoft SQL Server Always On Availability Group. You plan to configure a shared network location at \\DATA-CI1\SQL.
You need to create an availability group listener named AGL1 on port 1433.
In which order should you perform the actions? To answer, move all actions from the list of actions to the answer area and arrange them in the correct order.
Answer:
Explanation:
Explanation
Step 1: Launch the Failover Cluster Manager and..
To support theAlways On availability groups feature, ensure that every computer that is to participate in one or more availability groups meets requirements including:
* Ensure that each computer is a node in a WSFC (Windows Server Failover Clustering).
Step 2: Add andconfigure the replica and...
All the server instances that host availability replicas for an availability group must use the same SQL Server collation.
Step 3: Enable the SQL Server 2016 Always On Availability Group feature.
Enable the Always On availability groups feature on each server instance that will host an availability replica for any availability group. On a given computer, you can enable as many server instances for Always On availability groups as your SQL Server installation supports.
Step 4: Create the Always On Availability Group and..
Using Transact-SQL to create or configure an availability group listener Step 5: Select the Full data synchronization method and...
References: https://technet.microsoft.com/en-us/library/jj899851(v=sc.12).aspx
https://docs.microsoft.com/en-us/sql/database-engine/availability-groups/windows/create-or-configure-an-availab
NEW QUESTION: 3
A programmer must create a generic class MinMax and the type parameter of MinMax must implement Comparable. Which implementation of MinMax will compile?
A. class MinMax<E extends Comparable<E>> {
<E> E min = null;
<E> E max = null;
public MinMax() {}
public <E> void put(E value) { /* store min or max */ }
}
B. class MinMax<E implements Comparable<E>> {
<E> E min = null;
<E> E max = null;
public MinMax() {}
public <E> void put(E value) { /* store min or max */ }
}
C. class MinMax<E extends Comparable<E>> {
E min = null;
E max = null;
public MinMax() {}
public void put(E value) { /* store min or max */ }
}
D. class MinMax<E implements Comparable<E>> {
E min = null;
E max = null;
public MinMax() {}
public void put(E value) { /* store min or max */ }
}
Answer: C
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