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NEW QUESTION: 1
You have created a table based on the following data: EmpID NUMBER (5) PRIMARY KEY EmpName VARCHAR2 (35) NOT NULL Salary NUMBER (9, 2) NOT NULL Commission NUMBER (4, 2) ManagerName VARCHAR2 (25) ManagerID NUMBER (5) Now, you want to display the names of employees and their managers, using a self join. Which of the following SQL statements can you use to accomplish this? Each correct answer represents a complete solution. Choose two.
A. SELECT e.EmpName, m.ManagerName
FROM Employees e SELF JOIN Employeesm
ON e.EmpID = m.ManagerID;
B. SELECT e.EmpName, m.ManagerName
FROM Employees e, Employeesm
WHERE e.EmpID = m.ManagerID;
C. SELECT e.EmpName, m.ManagerNam e
FROM Employees e INNER JOIN Employeesm
ON e.EmpID = m.ManagerID;
D. SELECT e.EmpName, m.ManagerName
FROM Employees e LEFT OUTER JOIN Employees m
ON e.EmpID = m.ManagerID;
Answer: B,C
NEW QUESTION: 2
What capabilities does Huawei CSE Microservices provide for lifecycle management? (Multiple choice)
A. Service creation - local engineering, cloud engineering
B. Service monitoring---dashboard, docking APM
C. CCD---application development pipeline
D. Service Operation and Maintenance---Micro Service Management
Answer: A,B,C,D
NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
void print(int v) { cout<<v<<" "; }
struct Sequence {
int start;
Sequence(int start):start(start){}
int operator()() {
return 10*(1+(start++ %3));
}
};
int main() {
vector<int> v1(10);
generate_n(v1.begin(), 10, Sequence(1));
remove(v1.begin(), v1.end(), 10);
for_each(v1.begin(), v1.end(), print);cout<<endl;
return 0;
}
Program outputs:
A. compilation error
B. 20 30 20 30 20 30 20 30 10 20
C. 20 30 10 20 30 10 20 30 10 20
D. 20 30 20 30 20 30 20
Answer: B
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