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NEW QUESTION: 1
Service A carries out XML canonicalization and creates a message digest. It then encrypts
the message digest using asymmetric encryption. Service B.upon receiving the message,
decrypts the message hash and calculates the hash of the original message. However,
upon comparison, the received message digest and the calculated message digest do not
match. How can this problem be avoided?
A. Transforms need to be used so that Service B is provided the sequence of actions used
by Service A.
That way, Service B will know that it has to perform XML canonicalization on
the original message first, then calculate its hash, and only then compare it against the
decrypted message hash
B. XML canonicalization should not be performed because it is the cause of the mismatch
and will also unnecessarily increase the message size
C. None of the above
D. Transforms need to be used so that Service B is provided the sequence of actions used
by Service A.
That way, Service B will know that it has to calculate the original message's
hash first, and then perform XML canonicalization on the original message, and only then
compare it against the decrypted message hash
Answer: A
NEW QUESTION: 2
A. Corp-3
B. Corp-2
C. Branch-2
D. Corp-1
E. Corp-4
F. Branch-1
Answer: C,E
Explanation:
There are 2 segments on the topology above which are separated by Corp-3 router. Each segment will have a DR so we have 2 DRs.
To select which router will become DR they will compare their router-IDs. The router with
highest (best) router-ID will become DR. The router-ID is chosen in the order below:
The highest IP address assigned to a loopback (logical) interface.
If a loopback interface is not defined, the highest IP address of all active router's physical
interfaces will be chosen.
In this question, the IP addresses of loopback interfaces are not mentioned so we will
consider IP addresses of all active router's physical interfaces. Router Corp-4 (10.1.40.40)
& Branch-2 (10.2.20.20) have highest "active" IP addresses so they will become DRs.
NEW QUESTION: 3
When HTTP GET queries are used, which additional parameters can be used? (Select two.)
A. identify
B. start
C. multi resource
D. force
E. count
Answer: A,D
NEW QUESTION: 4
You administer laptops that run Windows 8 Enterprise. The laptops are members of an Active Directory domain and are configured with IPv6 disabled.
Some users require access to the internal company database servers while traveling.
You need to configure the requested network connection to the database servers.
What should you configure on the laptops?
A. A metered network connection
B. Out of band management
C. A DirectAccess connection to the company network
D. A virtual private network (VPN) connection to the company network
Answer: D
Explanation:
DirectAccess cannot be used in this case as IPv6 is disabled and DirectAccess requires IPv6 and IPsec.
IPv6 is the cornerstone of DirectAccess communications
The DirectAccess client always uses IPv6 to communicate with the DirectAccess server. The DirectAccess server will then forward these connections to IPv6-enabled hosts on the corpnet. The corpnet can use native IPv6 infrastructure (where the routers, switches, operating systems, and applications are all IPv6 capable) or it can use IPv6 transition technologies to connect to IPv6 resources on the corpnet.
Reference: http://www.techrepublic.com/blog/10things/10-things-you-should-know-aboutdirectaccess/1371
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