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NEW QUESTION: 1
What dimension is an example of a common structure dimension category?
Please choose the correct answer.
Response:
A. Location
B. Grade / Band
C. Employment Level
D. Job Family
Answer: A
NEW QUESTION: 2
プロジェクトマネージャーには、アクティビティの推定所要時間に関する次の情報があります。
-ほとんどの場合[tM]-15日
-悲観的[tP]-20日
-楽観的[tO]-10日
三角分布法によると、この活動の推定期間はどれくらいですか？
A. 5日
B. 15日
C. 10日
D. 12.5日
Answer: D
NEW QUESTION: 3
An airline maintains a fleet of 4-engine aircraft. Its maintenance records show that on the average an engine fails 3 times in 10,000 operating hours with normal preventive maintenance.
What is the Poisson distributed probability that 2 or more engines on an aircraft will fail during a typical flying period of 8 hours?
Response:
A. 0.0000029
B. 0.000034
C. 0.0000034
D. 0.000029
Answer: A
NEW QUESTION: 4
あなたは、あなたは、学生の年半ば成績を記録するためにStudentCode、SubjectCodeおよび成績カラムを持っているテーブルを作成します。 テーブルには様々な主題のために50の学生によって得られたマークがあります。あなたは、次の要件が満たされていることを確認する必要があります。
* 学生は彼らの平均点に基づいて評価されていなければなりません。
* 一人以上の学生が同じ平均点を持っている場合、同じランクはこれらの学生に与えられなければなりません。
* 同じランクが割り当てられる場合、連続するランクがスキップされなければなりません。
どのTransact-SQLクエリを使うべきでしょうか。
A. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
G. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: A
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms189798.aspx
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