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NEW QUESTION: 1
What is an advantage of using MTrees in an EMC Data Domain system?
A. Segregates management and replication traffic
B. Data from different MTrees are not deduplicated against each other
C. Allows for management of quotas separately
D. Allows selective data encryption
Answer: C
NEW QUESTION: 2
Block storage is a mode of storing data by block, and a block refers to the sector group on the underlying disk.
Which of the following statements regarding block storage is true?
A. Block storage can meet the requirement of a system containing thousands of CPUs.
B. Storage devices are cost-effective.
C. Block storage can provide high-performance random I/O and data throughput.
D. Block storage has good scalability and manageability.
Answer: C
NEW QUESTION: 3
A technician is building a custom gaming computer. Which of the following is the FASTEST memory the technician can use?
A. DDR3 CAS11
B. DDR2 CAS7
C. DDR3 CAS10
D. DDR3 CAS9
Answer: D
NEW QUESTION: 4
Sharleef Nettleton, a quantitative analyst with Churn Brothers Brokerage, is examining a data sample and has amassed the following information:
Standard deviation of the sample: 2.90
Number of observations: 68
Degrees of freedom: 2
Sample mean: 114
Assume that Ms. Nettleton formulates a null hypothesis that states that the value of the population mean is zero. Additionally, assume that the population standard deviation is unknown. Given this information, what is the standard error of the estimate? Further, what is the test statistic? Choose the best answer.
A. 0.3570; 319.38
B. None of these answers is correct.
C. 0.3517; 84.34
D. 1.0199; 111.78
E. 1.0199; 56.44
F. 0.3570; 29.91
G. 0.3517; 324.14
Answer: G
Explanation:
Explanation/Reference:
Explanation:
If the population standard deviation is unknown, as in this example, the standard error of the estimate is found by using the following equation:
{Standard error = s / square root of n} where s = the sample standard deviation and n = the number of observations in the sample.
In this example, all of the necessary information has been provided, and the determination of the standard error of the estimate is found as:
{Standard error = [2.90 / 8.2462] = 0.3517}
Now that the standard error of the estimate has been calculated, the test statistic can be found by using the following equation:
{Test statistic = [sample statistic - value of the population parameter under the null hypothesis] / standard error of the sample statistic].
Again, all of the necessary information has been provided, and the calculation of the test statistic is found as follows:
{Test statistic = [114 - 0] / 0.3517 = 324.14}
This is a very large test statistic and the null hypothesis will likely be rejected unless a very low level of confidence is employed.