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NEW QUESTION: 1
A. Option C
B. Option D
C. Option A
D. Option B
Answer: C
Explanation:
there are three profiles for Windows Firewall with Advanced Security: Profile Description
Domain Applied to a network adapter when it is connected to a network on which it can detect a domain controller of the domain to which the computer is joined. Private Applied to a network adapter when it is connected to a network that is identified by the user or administrator as a private network. A private network is one that is not connected directly to the Internet, but is behind some kind of security device, such as a network address translation (NAT) router or hardware firewall. For example, this could be a home network, or a business network that does not include a domain controller. The Private profile settings should be more restrictive than the Domain profile settings. Public Applied to a network adapter when it is connected to a public network such as those available in airports and coffee shops. When the profile is not set to Domain or Private, the default profile is Public. The Public profile settings should be the most restrictive because the computer is connected to a public network where the security cannot be controlled. For example, a program that accepts inbound connections from the Internet (like a file sharing program) may not work in the Public profile because the Windows Firewall default setting will block all inbound connections to programs that are not on the list of allowed programs. Each network adapter is assigned the firewall profile that matches the detected network type.
http://technet.microsoft.com/en-us/library/getting-started-wfas-firewall-profilesipsec%28v=ws.10%29.aspx
NEW QUESTION: 2
What is the subnet address of 192.168.1.42 255.255.255.248?
A. 192.168.1.40/29
B. 192.168.1.32/27
C. 192.168.1.48/29
D. 192.168.1.16/28
E. 192.168.1.8/29
Answer: A
Explanation:
Explanation
248 mask uses 5 bits (1111 1000) 42 IP in binary is (0010 1010) The base subnet therefore is the lowest binary value that can be written without changing the output of an AND operation of the subnet mask and IP ... 1111
1000 AND 0010 1010 equals 0010 1000 - which is .40 /24 is standard class C mask. adding the 5 bits from the .248 mask gives /29
NEW QUESTION: 3
Surface preparation methods for Non-ferrous metals are:
A. Not required
B. The same for all Non-FetT0us metals
C. The same as for Ferrous metals
D. Specific for each type of Non-ferrous metal
Answer: D
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