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NEW QUESTION: 1
Which of the following statements describe the operation of WRED on the Alcatel-Lucent 7750 SR? (Choose three)
A. WRED uses the shared buffer utilization, instead of the individual queue depth, to get a better picture of the average resource utilization of the shared buffer space.
B. WRED disables the TCP slow-start congestion control mechanism.
C. WRED uses two configurable slopes for each buffer pool: a high slope and a low slope.
D. WRED monitors the shared buffer space utilization over a period of time.
E. WRED polices the shared buffer pool and marks all packets above a certain rate as "discard eligible."
Answer: A
NEW QUESTION: 2
HOTSPOT
-The Foreign Exchange System (FXS) allows banking operations to monitor trades processed from different foreign exchange trading systems which are located in London, New York and Hong Kong.
-The Trade logical file is maintained using a series of batch jobs which copy each of the three foreign exchange data sets into FXS usable format. Once processed, the Add Trade batch function loads the data Into the Trade logical file and adds a date/time stamp.
-A Daily Trade Detail report is produced listing all trades monitored. This report is sorted by trading location.
-Two monthly reports are produced. A Monthly Summary Trade report is produced that contains summary trade numbers by trading location. A Monthly Trade Monitoring report is produced that lists all trades monitored, is sorted by trade date and contains a consolidated trade value.
From the Names of Possible Functions listed identify the base functional components for the FXS application. Select N/A if a Name of Possible Function Type does not apply.
Identify the functions used:
Answer:
Explanation:
NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <deque>
# include <iostream>
# include <algorithm>
# include <functional>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out; Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={20, 30, 10, 20, 30, 10, 20, 30, 10, 20};
deque<B> d1(t, t+10);
sort(d1.begin(), d1.end(), greater<B>());
pair<deque<B> ::iterator, deque<B>::iterator > result = equal_range(d1.begin(), d1.end(),
B(20), greater<B>());
for_each(result.first, result.second, Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 30 20 20 20 20 10
B. 20 20 20 20 10
C. 20 20 20 20
D. 30 30 30 20 20 20 20 10 10 10
E. 30 20 20 20 10
Answer: C