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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The domain contains a server named Server1.
Server1 runs Windows Server 2012 R2 and has the Hyper-V server role installed.
You have a virtual machine named VM1. VM1 has a checkpoint.You need to modify the Checkpoint File Location of
VM1.
What should you do first?
A. Copy the checkpoint file
B. Shut down VM1
C. Delete the checkpoint
D. Pause VM1
Answer: C
NEW QUESTION: 2
What defines the time taken to position the read/write head across the platter with a radial movement in a disk drive?
A. Data transfer time
B. Service time
C. Rotational latency
D. Seek time
Answer: D
Explanation:
Seek Time The seek time (also called access time) describes the time taken to position the R/W heads across the platter with a radial movement (moving along the radius of the platter). In other words, it is the time taken to position and settle the arm and the head over the correct
track.
Therefore, the lower the seek time, the faster the I/O operation. Disk vendors publish the
following seek time specifications:
Full Stroke: The time taken by the R/W head to move across the entire width of the disk,
from the innermost track to the outermost track.
Average: The average time taken by the R/W head to move from one random track to
another, normally listed as the time for one-third of a full stroke.
Track-to-Track: The time taken by the R/W head to move between adjacent tracks.
Each of these specifications is measured in milliseconds. The seek time of a disk is
typically specified by the drive manufacturer. The average seek time on a modern disk is
typically in the range of 3 to 15 milliseconds. Seek time has more impact on the I/O
operation of random tracks rather than the adjacent tracks. To minimize the seek time, data
can be written to only a subset of the available cylinders. This results in lower usable
capacity than the actual capacity of the drive. For example, a 500-GB disk drive is set up to
use only the first 40 percent of the cylinders and is effectively treated as a 200-GB drive.
This is known as short stroking the drive.
EMC E10-001 Student Resource Guide. Module 2: Data Center Environment
NEW QUESTION: 3
コスト差異(CV)は達成額に等しい:
A. Minus actual cost [EV - AC].
B. Minus planned value [EV - PV].
C. Divided by actual cost [EV/AC].
D. Divided by planned value [EV/PV].
Answer: A