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NEW QUESTION: 1
Which characteristic of an IS-IS single topology is true?
A. It supports asymmetric IPv4 and IPv6 interface.
B. The metric-style wide command must be enabled.
C. It uses a separate SPF calculation than the IPv4 routing table
D. Its IPv4 and IPv6 interfaces must have a 1:1 correlation.
Answer: D
NEW QUESTION: 2
HOTSPOT
Answer:
Explanation:
Explanation:
Windows Updates will be downloaded from Windows Server Update Services only. This is determined by the "Specify Intranet Microsoft Update Service Location" setting and the "Do not connect to any Windows Update Internet locations" setting both being 'Enabled'.
In the "Specify Intranet Microsoft Update Service Location" setting, you can specify the name of the Windows Server Updates Services server.
If a user is logged into the computer and an update requires a restart, the computer will restart when the user signs out. This is determined by the "No auto-restart with logged on users for schedule automatic updates" setting being enabled. This group policy setting creates a registry key named NoAutoRebootWithLoggedOnUsers and sets the value of the key to 1 (enabled).
With this setting enabled, you should be aware that the computer should be restarted at the earliest opportunity in order to complete the installation of the Windows Updates.
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:
Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
Answer: A
NEW QUESTION: 4
A. Option C
B. Option D
C. Option B
D. Option A
Answer: C
Explanation:
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